Propane molecule on chlorination under photochemical condition gives two di-chloro products, “x” and “y”. Amongst “x” and “y”, “x” is an optically active molecule. How many tri-chloro products (consider only structural isomers) will be obtained from “x” when it is further treated with chlorine under the photochemical condition?
- 4
- 2
- 3
- 5
Answer
(3) 3
Solution
Concept: x is the dichloride with a chiral carbon: 1,2-dichloropropane.
[figure]
x has 3 kinds of C–H (CH2Cl, CHCl, CH3) ⇒ 3 trichloro isomers.
Answer: (3)