A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 μF capacitor. The rate of change of potential difference across the plates of the capacitor is nearly 106 V/s. The value of is .
- 0.58
- 0.67
- 0.82
- 0.75
Answer
(2) 0.67
Solution
The displacement current is
Id = 0 d Edt = 0A ddt ( Vd ) = C dVdt
dVdt = IdC = 4.06 10-6 V/s
dVdt = 0.67 106 V/s
∴ 0.67
Answer: (2)