Acceleration due to gravity on the surface of earth is 'g'. If the diameter of earth is reduced to one third of its original value and mass remains unchanged, then the acceleration due to gravity on the surface of earth is g.
Answer
9
Solution
g= GMR2 g 1R2 (mass fixed).
Diameter 13 R'= R3
g'= GM(R/3)2=9g
Answer: 9