In a Young's double slit experiment, the intensity at a point is ( 14 )th of the maximum intensity, the minimum distance of the point from the central maximum is . (Given : = 600 nm, d = 1.0 mm, D = 1.0 m)
200
I = Imax 2 2 = Imax4 2 = 12
The smallest phase difference is = 2 3,
so the path difference ydD = 2 = 3
y = D3d = 600 10-9 13 10-3
= 2 10-4 m = 200
Answer: 200
Monochromatic light of wavelength 500 nm is used in Young's double slit experiment. An interference pattern is obtained on a screen. When one of the slits is covered with a very thin glass plate (refractive index = 1.5), the central maximum is shifted to a position previously occupied by the 4th bright fringe. The thickness of the glass-plate is .
A parallel beam of monochromatic light of wavelength 600 nm passes through single slit of 0.4 mm width. Angular divergence corresponding to second order minima would be 10-3 rad.
Two slits are 1 mm apart and the screen is located 1 m away from the slits. A light of wavelength 500 nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is 10-4 m.
Two coherent monochromatic light beams of intensities I and 4I are superimposed. The difference between maximum and minimum possible intensities in the resulting beam is x I. The value of x is .
Light emerges out of a convex lens when a source of light is kept at its focus. The shape of wavefront of the light is :
In Young's double slit experiment, carried out with light of wavelength 5000 Å, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0 cm. The value of x for third maxima is mm.
In a single slit experiment, a parallel beam of green light of wavelength 550 nm passes through a slit of width 0.20 mm. The transmitted light is collected on a screen 100 cm away. The distance of first order minima from the central maximum will be x 10-5 m. The value of x is :
Two wavelengths 1 and 2 are used in Young's double slit experiment. 1=450 nm and 2=650 nm. The minimum order of fringe produced by 2 which overlaps with the fringe produced by 1 is n. The value of n is .
The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is:
A monochromatic light of wavelength 6000 is incident on the single slit of width 0.01 mm. If the diffraction pattern is formed at the focus of the convex lens of focal length 20 cm, the linear width of the central maximum is :