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System of Particles and Rotational Motion

JEE Main 2025 (Online) 8th April Evening ShiftNumericalMedium📈 Topic in 22% papers+4
Ques. 1JEE Main 2025, 8 April (Evening Shift)

A thin solid disk of 1 kg is rotating along its diameter axis at the speed of 1800 rpm. By applying an external torque of 25 N m for 40 s, the speed increases to 2100 rpm. The diameter of the disk is m.

Answer

40

Solution

Change in angular speed: = (2100 - 1800) rpm = 300 2 60 = 10 rad/s

Angular acceleration: = t = 10 40 = 4 rad/s2

= I I = 25 /4 = 100 kg m2

For a thin disk about a diameter: I = 14MR2

14 1 R2 = 100 R = 20 m

Diameter = 2R = 40 m

Answer: 40

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Ques. 2JEE Main 2025, 7 April (Morning Shift)

A rod of length 5 L is bent at right angle keeping one side length as 2 L. [figure] The position of the centre of mass of the system : (Consider L = 10 cm)

  1. 4 i + 9 j
  2. 2 i + 3 j
  3. 5 i + 8 j
  4. 3 i + 7 j
Ques. 3JEE Main 2025, 7 April (Morning Shift)

A, B and C are disc, solid sphere and spherical shell respectively with same radii and masses. These masses are placed as shown in figure. [figure] The moment of inertia of the given system about PQ axis is x15I, where I is the moment of inertia of the disc about its diameter. The value of x is .

Ques. 4JEE Main 2025, 7 April (Evening Shift)

Let M and R be the mass and radius of a disc. A small disc of radius R/3 is removed from the bigger disc as shown in figure. The moment of inertia of remaining part of bigger disc about an axis passing through the centre O and perpendicular to the plane of disc is 4xMR2. The value of x is . [figure]

Ques. 5JEE Main 2025, 4 April (Morning Shift)

Which of the following are correct expressions for torque acting on a body? ( r = position vector; p = linear momentum; L = angular momentum; = angular acceleration; I = moment of inertia; F = force; t = time) Choose the correct answer from the options given below:

  1. A, B, D and E Only
  2. C and D Only
  3. B, C, D and E Only
  4. B, D and E Only
Ques. 6JEE Main 2025, 4 April (Morning Shift)

A circular ring and a solid sphere having same radius roll down on an inclined plane from rest without slipping. The ratio of their velocities when reached at the bottom of the plane is x5 where x = .

Ques. 7JEE Main 2025, 4 April (Evening Shift)

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m/s. The speed of the particle on the rim of the wheel at the same level as the centre of the wheel, will be :

  1. 4 2 m/s
  2. 8 m/s
  3. 4 m/s
  4. 8 2 m/s
Ques. 8JEE Main 2025, 4 April (Evening Shift)

A solid sphere with uniform density and radius R is rotating initially with constant angular velocity ( 1) about its diameter. After some time during the rotation it starts losing mass at a uniform rate, with no change in its shape. The angular velocity of the sphere when its radius becomes R/2 is x 1. The value of x is .

Ques. 9JEE Main 2025, 3 April (Morning Shift)

A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg, kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is [figure]

  1. 2.5 m/s2
  2. 3.5 m/s2
  3. 0.25 m/s2
  4. 0.35 m/s2
Ques. 10JEE Main 2025, 2 April (Morning Shift)

Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is ' '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

  1. /4
  2. /8
  3. /2
Ques. 11JEE Main 2025, 2 April (Morning Shift)

A square lamina OABC of length 10 cm is pivoted at 'O'. Forces act at lamina as shown in figure. If lamina remains stationary, then the magnitude of F is : [figure]

  1. 10 N
  2. 0 (zero)
  3. 10 2 N
  4. 20 N

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