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Relations and Functions

JEE Main 2025 (Online) 8th April Evening ShiftNumericalMedium📈 Topic in 34% papers+4
Ques. 1JEE Main 2025, 8 April (Evening Shift)

Let the domain of the function f(x) = -1 ( 4x + 53x - 7 ) be [ , ] and the domain of g(x) = 2 (2 - 6 27(2x + 5) ) be ( , ). Then |7( + ) + 4( + )| is equal to .

Answer

96

Solution

For f: -1 4x + 53x - 7 1

4x + 53x - 7 - 1 0 x + 123x - 7 0 -12 x < 73

4x + 53x - 7 + 1 0 7x - 23x - 7 0 x 27 or x > 73

domain = [-12, 27 ], so + = -12 + 27 = - 827

For g: 2x + 5 > 0 x > - 52

and 2 - 6 27(2x + 5) > 0 27(2x + 5) < 13 2x + 5 < 27 13 = 3 x < -1

domain = (- 52, -1 ), so + = - 72

|7( + ) + 4( + )| = |-82 - 14| = 96

Answer: 96

Keep practising — Relations and Functions

Ques. 2JEE Main 2025, 7 April (Evening Shift)

If the range of the function f(x) = 5-xx2-3x+2, x 1, 2, is (- , ] [ , ), then 2 + 2 is equal to :

  1. 188
  2. 192
  3. 190
  4. 194
Ques. 3JEE Main 2025, 4 April (Evening Shift)

Let the domains of the functions f(x) = 4 3 7 (8 - 2 (x2 + 4x + 5 ) ) and g(x) = -1 ( 7x + 10x - 2 ) be ( , ) and [ , ], respectively. Then 2 + 2 + 2 + 2 is equal to :

  1. 15
  2. 13
  3. 16
  4. 14
Ques. 4JEE Main 2025, 3 April (Morning Shift)

If the domain of the function f(x) = e ( 2x-35+4x ) + -1 ( 4+3x2-x ) is [ , ), then 2 + 4 is equal to

  1. 4
  2. 3
  3. 7
  4. 5
Ques. 5JEE Main 2025, 3 April (Evening Shift)

If the domain of the function f(x) = 7 (1 - 4 (x2 - 9x + 18 ) ) is ( , ) ( , ), then + + + is equal to

  1. 17
  2. 15
  3. 16
  4. 18
Ques. 6JEE Main 2025, 2 April (Evening Shift)

Let A = \1, 2, 3, , 100\ and R be a relation on A such that R = \(a, b) : a = 2b + 1\. Let (a1, a2), (a2, a3), (a3, a4), , (ak, ak+1) be a sequence of k elements of R such that the second entry of an ordered pair is equal to the first entry of the next ordered pair. Then the largest integer k, for which such a sequence exists, is equal to :

  1. 6
  2. 8
  3. 7
  4. 5
Ques. 7JEE Main 2025, 2 April (Evening Shift)

If the domain of the function f(x) = 1 10 + 3x - x2 + 1 x + |x| is (a, b), then (1 + a)2 + b2 is equal to :

  1. 29
  2. 30
  3. 25
  4. 26
Ques. 8JEE Main 2025, 29 January (Evening Shift)

Let S = N \0\. Define a relation R from S to R by : R = \(x, y) : e y = x e ( 25 ), x S, y R \. Then, the sum of all the elements in the range of R is equal to :

  1. 32
  2. 109
  3. 52
  4. 53
Ques. 9JEE Main 2025, 29 January (Evening Shift)

If the domain of the function 5(18x - x2 - 77) is ( , ) and the domain of the function (x-1) ( 2x2 + 3x - 2x2 - 3x - 4 ) is ( , ), then 2 + 2 + 2 is equal to:

  1. 186
  2. 179
  3. 195
  4. 174
Ques. 10JEE Main 2025, 28 January (Morning Shift)

Let f : R R be a function defined by f(x) = (2 + 3a)x2 + ( a+2a-1 )x + b, a 1. If f(x + y) = f(x) + f(y) + 1 - 27xy, then the value of 28 i=15|f(i)| is

  1. 735
  2. 675
  3. 715
  4. 545
Ques. 11JEE Main 2025, 24 January (Evening Shift)

The number of real solution(s) of the equation x2+3x+2= \|x-3|,|x+2|\ is :

  1. 2
  2. 3
  3. 1
  4. 0

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