Two different adiabatic paths for the same gas intersect two isothermal curves as shown in P-V diagram. The relation between the ratio VaVd and the ratio VbVc is: [figure]
- VaVd VbVc
- VaVd = ( VbVc )-1
- VaVd = VbVc
- VaVd = ( VbVc )2
Answer
(3) VaVd = VbVc
Solution
a, b on isotherm T1; d, c on isotherm T2
Adiabatic: TV - 1 = constant
a → d: T1Va - 1 = T2Vd - 1
b → c: T1Vb - 1 = T2Vc - 1
Dividing: ( VaVb ) - 1 = ( VdVc ) - 1
VaVb = VdVc VaVd = VbVc
Answer: (3)