A particle is released from height S above the surface of the earth. At certain height its kinetic energy is three times its potential energy. The height from the surface of the earth and the speed of the particle at that instant are respectively.
- S4, 3gS2
- S2, 3gS2
- S4, 3gS2
- S2, 3gS2
Answer
(3) S4, 3gS2
Solution
Take potential energy zero at the surface (g uniform); at height h the kinetic energy is K = 3U = 3mgh.
Since the particle is released from rest at S, conservation of mechanical energy gives
mgS = mgh + 3mgh = 4mgh
h = S4
Then 12mv2 = 3mg S4
v = 3gS2
Answer: (3)