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Coordination Compounds

JEE Main 2025 (Online) 7th April Evening ShiftMatchingMedium📈 Topic in 10% papers+4−1
Ques. 1JEE Main 2025, 7 April (Evening Shift)

Match List - I with List - II. Choose the correct answer from the options given below :

  1. A-I, B-III, C-II, D-IV
  2. A-II, B-III, C-IV, D-I
  3. A-I, B-IV, C-IV, D-III
  4. A-III, B-I, C-II, D-IV

Answer

(3) A-I, B-IV, C-IV, D-III

Solution

As per Werner's theory, primary valency = oxidation state of the central metal and secondary valency = coordination number.

(A) [Co(en)2Cl2]Cl: x + 0 + 2(-1) = +1 x = +3; donor atoms = 2 2 (en) + 2 (Cl) = 6 (3, 6) → I

(B) [Pt(NH3)2Cl(NO2)]: x + 0 - 1 - 1 = 0 x = +2; four monodentate ligands, CN = 4 (2, 4) → IV

(C) Hg[Co(SCN)4]: Hg2+ [Co(SCN)4]2-; x + 4(-1) = -2 x = +2; CN = 4 (2, 4) → IV

(D) [Mg(EDTA)]2-: EDTA4- x - 4 = -2 x = +2; EDTA is hexadentate, CN = 6 (2, 6) → III

A-I, B-IV, C-IV, D-III

Answer: (3)

Keep practising — Coordination Compounds

Ques. 2JEE Main 2025, 7 April (Evening Shift)

The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively : [Fe(CN)6]3-, [FeF6]3-, [CoF6]3-, [Mn(CN)6]3-

  1. 1, 5, 4, 2
  2. 1, 4, 4, 2
  3. 1, 5, 5, 2
  4. 1, 1, 4, 2
Ques. 3JEE Main 2025, 7 April (Evening Shift)

The number of paramagnetic metal complex species among [Co(NH3)6]3+, [Co(C2O4)3]3-, [MnCl6]3-, [Mn(CN)6]3-, [CoF6]3-, [Fe(CN)6]3- and [FeF6]3- with same number of unpaired electrons is .

Ques. 4JEE Main 2025, 4 April (Morning Shift)

Which one of the following complexes will have o = 0 and = 5.96 B.M.?

  1. [FeF6]4-
  2. [Mn(SCN)6]4-
  3. [Co(NH3)6]3+
  4. [Fe(CN)6]4-
Ques. 5JEE Main 2025, 4 April (Morning Shift)

Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl2(ox)2]3- are respectively (py = pyridine, ox = oxalate)

  1. 3 & 3
  2. 2 & 3
  3. 1 & 2
  4. 2 & 2
Ques. 6JEE Main 2025, 4 April (Evening Shift)

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [FeCl6]3-, [Fe(C2O4)3]3- and [Fe(H2O)6]3+. The nature of oxide of vanadium of the type V2OX is :

  1. Amphoteric
  2. Acidic
  3. Basic
  4. Neutral
Ques. 7JEE Main 2025, 4 April (Evening Shift)

The correct order of [FeF6]3-, [CoF6]3-, [Ni(CO)4] and [Ni(CN)4]2- complex species based on the number of unpaired electrons present is:

  1. [CoF6]3- > [FeF6]3- > [Ni(CO)4] > [Ni(CN)4]2-
  2. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- > [Ni(CO)4]
  3. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- = [Ni(CO)4]
  4. [Ni(CN)4]2- > [FeF6]3- > [CoF6]3- > [Ni(CO)4]
Ques. 8JEE Main 2025, 4 April (Evening Shift)

A metal complex with a formula MCl4 3NH3 is involved in sp3d2 hybridisation. It upon reaction with excess of AgNO3 solution gives 'x' moles of AgCl. Consider 'x' is equal to the number of lone pairs of electrons present in the central atom of BrF5. Then the number of geometrical isomers exhibited by the complex is .

Ques. 9JEE Main 2025, 3 April (Morning Shift)

The correct order of the complexes [Co(NH3)5(H2O)]3+ (A), [Co(NH3)6]3+ (B), [Co(CN)6]3- (C) and [CoCl(NH3)5]2+ (D) in terms of wavelength of light absorbed is

  1. D > C > B > A
  2. C > B > A > D
  3. D > A > B > C
  4. C > B > D > A
Ques. 10JEE Main 2025, 3 April (Morning Shift)

The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is . FeCl3 + KOH + H2C2O4 A

Ques. 11JEE Main 2025, 3 April (Evening Shift)

Identify the diamagnetic octahedral complex ions from below ; Choose the correct answer from the options given below:

  1. B and C Only
  2. A and C Only
  3. B and D Only
  4. A and D Only

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