Decomposition of a hydrocarbon follows the equation k = (5.5 1011 s-1) e-28000 K/T. The activation energy of reaction is kJ mol-1. (Nearest Integer) Given : R = 8.3 J K-1 mol-1
Answer
232
Solution
By the Arrhenius equation, k = Ae-Ea/RT.
Comparing it with k = (5.5 1011 s-1) e-28000 K/T gives
EaR = 28000 K
Ea = 28000 × 8.3 = 232400 J mol-1
Ea ≈ 232 kJ mol-1
Answer: 232