An air bubble of radius 1.0 mm is observed at a depth 20 cm below the free surface of a liquid having surface tension 0.095 J/m2 and density 103 kg/m3. The difference between pressure inside the bubble and atmospheric pressure is N/m2. (Take g=10 m/s2)
Answer
2190
Solution
Pressure in the liquid at depth h is Patm+ gh; an air bubble has one surface, adding 2Tr.
[figure]
Pin-Patm= gh+ 2Tr=103 10 0.2+ 2 0.09510-3
=2000+190=2190 N/m2
Answer: 2190