The output Y of following circuit for given inputs is : [figure]
- A B
- A B
- A B(A + B)
- 0
Answer
(4) 0
Solution
[figure]
The OR gate gets A and B, so it gives A + B; the lower AND gate gets A and B, so it gives A B. The last AND gate gives Y = (A + B) AB.
Truth table:
array|c|c|c|c|c| A & B & A + B & A B & Y \ 0 & 0 & 1 & 0 & 0 \ 0 & 1 & 0 & 1 & 0 \ 1 & 0 & 1 & 0 & 0 \ 1 & 1 & 1 & 0 & 0 \ array
Whenever one input of the last AND gate is 1 the other is 0, so Y = 0 for every input.
(1): A B = 1 for A = B = 1, so (1) is wrong
(2): A B = 1 for A = 0, B = 1, so (2) is wrong
(3): A B(A + B) = 1 for A = B = 1, so (3) is wrong
Answer: (4)