A B The molecule A changes into its isomeric form B by following a first order kinetics at a temperature of 1000 K. If the energy barrier with respect to reactant energy for such isomeric transformation is 191.48 kJ mol-1 and the frequency factor is 1020, the time required for 50\% molecules of A to become B is picoseconds (nearest integer). [R=8.314 J K-1 mol-1 ]
Answer
69
Solution
EaRT = 191.48 1038.314 1000 = 23.03 = 10 10
k = A e-Ea/RT = 1020 10-10 = 1010 s-1
t1/2 = 0.6931010 = 69.3 ps 69
Answer: 69