In a hydrogen like ion, the energy difference between the 2nd excitation energy state and ground is 108.8 eV. The atomic number of the ion is:
(3) 3
The second excited state is n = 3 and the ground state is n = 1. For a hydrogen-like ion En = - 13.6 Z2n2 eV, so
E = 13.6 Z2 ( 112 - 132 ) = 13.6 Z2 89
Hence
13.6 Z2 89 = 108.8
Z2 = 108.8 913.6 8 = 9
Z = 3
Answer: (3)
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