The compound which shows metamerism is :
- C4H10O
- C5H12
- C3H8O
- C3H6O
Answer
(1) C4H10O
Solution
Metamerism arises from different alkyl groups on either side of a polyvalent functional group (e.g. –O–), so C4H10O, which forms the ethers CH3-O-C3H7 and C2H5-O-C2H5, shows it; these two are metamers.
C5H12 (alkane) has no functional group, C3H8O has only one ether, CH3-O-C2H5, and C3H6O (propanal / propanone) has only one carbonyl compound of each type.
∴ C4H10O shows metamerism.
Answer: (1)