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Isomerism

NEET (UG) 2021MCQEasy📈 Topic in 25% papers+4−1
Ques. 1NEET (UG) 2021

The compound which shows metamerism is :

  1. C4H10O
  2. C5H12
  3. C3H8O
  4. C3H6O

Answer

(1) C4H10O

Solution

Metamerism arises from different alkyl groups on either side of a polyvalent functional group (e.g. –O–), so C4H10O, which forms the ethers CH3-O-C3H7 and C2H5-O-C2H5, shows it; these two are metamers.

C5H12 (alkane) has no functional group, C3H8O has only one ether, CH3-O-C2H5, and C3H6O (propanal / propanone) has only one carbonyl compound of each type.

∴ C4H10O shows metamerism.

Answer: (1)

Keep practising — Isomerism

Ques. 2NEET (UG) 2021

Dihedral angle of least stable conformer of ethane is :

  1. 0
  2. 120
  3. 180
  4. 60
Ques. 3NEET 2017

With respect to the conformers of ethane, which of the following statements is true?

  1. Bond angle changes but bond length remains same.
  2. Both bond angle and bond length change.
  3. Both bond angle and bond length remain same.
  4. Bond angle remains same but bond length changes.
Ques. 4NEET 2016 (Phase 1)

Which of the following biphenyls is optically active ?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 5NEET 2016 (Phase 1)

The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is

  1. the eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
  2. the staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
  3. the staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
  4. the eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
Ques. 6NEET 2016 (Phase 1)

The correct statement regarding a carbonyl compound with a hydrogen atom on its alpha-carbon, is

  1. a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as carbonylation
  2. a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as keto-enol tautomerism
  3. a carbonyl compound with a hydrogen atom on its alpha-carbon never equilibrates with its corresponding enol
  4. a carbonyl compound with a hydrogen atom on its alpha-carbon rapidly equilibrates with its corresponding enol and this process is known as aldehyde-ketone equilibration.
Ques. 7NEET 2016 (Phase 2)

Which among the given molecules can exhibit tautomerism? [figure]

  1. III only
  2. Both I and III
  3. Both I and II
  4. Both II and III
Ques. 8AIPMT 2015

The possible stereo-structures of CH3CHOHCOOH, which are optically active, are called

  1. atropisomers
  2. enantiomers
  3. mesomers
  4. diastereomers
Ques. 9AIPMT 2015

In an SN1 reaction on chiral centers, there is

  1. inversion more than retention leading to partial racemisation
  2. 100% retention
  3. 100% inversion
  4. 100% racemisation
Ques. 10AIPMT 2015

The number of structural isomers possible from the molecular formula C3H9N is

  1. 5
  2. 2
  3. 3
  4. 4
Ques. 11AIPMT 2015 (Cancelled)

Given : [figure] Which of the given compounds can exhibit tautomerism?

  1. II and III
  2. I, II and III
  3. I and II
  4. I and III

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