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JEE Main 2026 (Online) 24th January Morning ShiftMCQEasy📈 Topic in 19% papers+4−1
Ques. 1JEE Main 2026, 24 January (Morning Shift)

A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass 60 g mol-1 and 0.9 g of a non-volatile non-electrolyte solute 'B' of molar mass 180 g mol-1 in 100 mL H2O at 27 . Osmotic pressure of the solution will be [Given: R = 0.082 L atm K-1 mol-1]

  1. 2.46 atm
  2. 0.82 atm
  3. 1.47 atm
  4. 1.23 atm

Answer

(1) 2.46 atm

Solution

Osmotic pressure depends on the total number of solute particles: = (nA + nB)VRT

nA = 0.360 = 0.005 mol, nB = 0.9180 = 0.005 mol

nA + nB = 0.01 mol; V = 100 mL = 0.1 L; T = 300 K

= 0.010.1 0.082 300

= 0.1 24.6 = 2.46 atm

Answer: (1)

Keep practising — Solutions

Ques. 2JEE Main 2026, 24 January (Morning Shift)

'W' g of a non-volatile electrolyte solid solute of molar mass 'M' g mol-1 when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg. If aqueous solution of the electrolyte boils at 375 K and Kb for water is 0.52 K kg mol-1, then the mole fraction of the electrolyte solute (x2) in the solution can be expressed as (Given : density of water = 1 g/mL and boiling point of water = 373 K)

  1. 162.6 WM
  2. 1.38 MW
  3. 2.616 MW
  4. 1.38 WM
Ques. 3JEE Main 2026, 24 January (Evening Shift)

At 298 K, the mole percentage of N2(g) in air is 80\%. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of N2(g) in water at 298 K? (KH for N2 is 6.5 107 mmHg)

  1. 9.35 10-5
  2. 9.35 105
  3. 1.23 10-7
  4. 1.17 10-4
Ques. 4JEE Main 2026, 24 January (Evening Shift)

Two liquids A and B form an ideal solution at temperature T K. At T K, the vapour pressures of pure A and B are 55 and 15 kN m-2 respectively. What is the mole fraction of A in solution of A and B in equilibrium with a vapour in which the mole fraction of A is 0.8?

  1. 0.5217
  2. 0.480
  3. 0.340
  4. 0.663
Ques. 5JEE Main 2026, 23 January (Morning Shift)

Which one of the following graphs accurately represents the plot of partial pressure of CS2 vs its mole fraction in a mixture of acetone and CS2 at constant temperature?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 6JEE Main 2026, 23 January (Evening Shift)

Two liquids A and B form an ideal solution. At 320 K, the vapour pressure of the solution, containing 3 mol of A and 1 mol of B is 500 mm Hg. At the same temperature, if 1 mol of A is further added to this solution, vapour pressure of the solution increases by 20 mm Hg. Vapour pressure (in mm Hg) of B in pure state is . (Nearest integer)

Ques. 7JEE Main 2026, 22 January (Morning Shift)

Consider a solution of CO2(g) dissolved in water in a closed container. Which one of the following plots correctly represents variation of log (partial pressure of CO2 in vapour phase above water) [y-axis] with log (mole fraction of CO2 in water) [x-axis] at 25 ?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 8JEE Main 2026, 22 January (Morning Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are true
  2. Statement I is true but Statement II is false
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are false
Ques. 9JEE Main 2026, 21 January (Morning Shift)

Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and PQ2. When 1 g of PQ is dissolved in 50 g of solvent 'A', Tb was 1.176 K while when 1 g of PQ2 is dissolved in 50 g of solvent 'A', Tb was 0.689 K. (Kb of 'A' = 5 K kg mol-1). The molar masses of elements P and Q (in g mol-1) respectively, are :

  1. 25, 60
  2. 60, 25
  3. 65, 145
  4. 70, 110
Ques. 10JEE Main 2026, 21 January (Evening Shift)

The osmotic pressure of a living cell is 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is g L-1. (Nearest integer) Given : R = 0.08 L atm K-1 mol-1 Assume complete dissociation of NaCl (Given: Molar mass of Na and Cl are 23 and 35.5 g mol-1 respectively.)

Ques. 11JEE Main 2026, 21 January (Evening Shift)

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol-1) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is 10-2. (nearest integer) [Given: Kb of the solvent = 5.0 K kg mol-1] Assume the solution to be dilute and no association or dissociation of X takes place in solution.

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