Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at -24 is kg (Molar mass in g mol-1 for ethylene glycol 62, Kf of water = 1.86 K kg mol-1)
Solutions
Previous year questions with solutions · 2024 – 2026
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 23 | 19 | 1.2 | 4.84% ▼ 4.2% vs last year |
| 2025 | 24 | 19 | 1.3 | 5.05% ▲ 38% vs last year |
| 2024 | 22 | 21 | 1 | 3.66% |
Identify the mixture that shows positive deviations from Raoult's Law
- (CH3)2CO + CS2
- (CH3)2CO + C6H5NH2
- CHCl3 + C6H6
- CHCl3 + (CH3)2CO
What happens to freezing point of benzene when small quantity of naphthalene is added to benzene?
- Increases
- Decreases
- Remains unchanged
- First decreases and then increases
The solution from the following with highest depression in freezing point/lowest freezing point is
- 180 g of acetic acid dissolved in benzene
- 180 g of acetic acid dissolved in water
- 180 g of benzoic acid dissolved in benzene
- 180 g of glucose dissolved in water
If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nA, nB and nC. Mole fraction of C in the solution is
- nCnA nB nC
- nBnA+nB
- nCnA+nB+nC
- nCnA-nB-nC
The osmotic pressure of a dilute solution is 7 105 Pa at 273 K. Osmotic pressure of the same solution at 283 K is 104 Nm-2.
Molality of 0.8 M H2SO4 solution (density 1.06 g cm-3) is 10-3 m.
A solution of two miscible liquids showing negative deviation from Raoult's law will have :
- increased vapour pressure, increased boiling point
- increased vapour pressure, decreased boiling point
- decreased vapour pressure, decreased boiling point
- decreased vapour pressure, increased boiling point
The quantity which changes with temperature is :
- Molality
- Molarity
- Mole fraction
- Mass percentage