Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Application of Integrals

JEE Main 2025 (Online) 2nd April Morning ShiftNumericalMedium📈 Topic in 71% papers+4
Ques. 1JEE Main 2025, 2 April (Morning Shift)

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

Answer

22

Solution

|4 - x2| x2: for 0 x 2 this needs 4 - x2 x2 x 2; for x 2 it always holds.

For x 2: y 4 and y x2 - 4 x2 - 4 4 x 2 2

Part 1 ( 2 x 2): 4 - x2 y x2

A1 = 22 (2x2 - 4) dx = [ 2x33 - 4x ] 22

= ( 163 - 8 ) - ( 4 23 - 4 2 ) = 8 23 - 83

Part 2 (2 x 2 2): x2 - 4 y 4

A2 = 22 2 (8 - x2) dx = [8x - x33 ]22 2

= (16 2 - 16 23 ) - (16 - 83 ) = 32 23 - 403

Area = A1 + A2 = 40 23 - 16 = 80 26 - 16

= 6, = 16

+ = 22

Answer: 22

Keep practising — Application of Integrals

Ques. 2JEE Main 2025, 29 January (Morning Shift)

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
Ques. 3JEE Main 2025, 29 January (Evening Shift)

Let the area enclosed between the curves |y|=1-x2 and x2+y2=1 be . If 9 = + ; , are integers, then the value of | - | equals:

  1. 15
  2. 18
  3. 33
  4. 27
Ques. 4JEE Main 2025, 28 January (Morning Shift)

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
Ques. 5JEE Main 2025, 28 January (Evening Shift)

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
Ques. 6JEE Main 2025, 24 January (Morning Shift)

The area of the region \(x,y):x2+4x+2 y |x+2| \ is equal to

  1. 7
  2. 24/5
  3. 20/3
  4. 5
Ques. 7JEE Main 2025, 24 January (Evening Shift)

The area of the region enclosed by the curves y=ex, y=|ex-1| and y-axis is :

  1. 1+ e2
  2. e2
  3. 1- e2
  4. 2 e2-1
Ques. 8JEE Main 2025, 23 January (Morning Shift)

If the area of the larger portion bounded between the curves x2+y2=25 and y=|x-1| is 14(b +c), b,c , then b+c is equal to

Ques. 9JEE Main 2025, 23 January (Evening Shift)

If the area of the region \(x,y):-1 x 1, 0 y a+e|x|-e-x, a>0 \ is e2+8e+1e, then the value of a is :

  1. 7
  2. 5
  3. 6
  4. 8
Ques. 10JEE Main 2025, 22 January (Morning Shift)

The area of the region, inside the circle (x-2 3)2+y2=12 and outside the parabola y2=2 3 x is :

  1. 3 -8
  2. 6 -8
  3. 3 +8
  4. 6 -16
Ques. 11JEE Main 2025, 22 January (Morning Shift)

Let f:R be a twice differentiable function such that f(x+y)=f(x)f(y) for all x,y . If f'(0)=4a and f satisfies f''(x)-3af'(x)-f(x)=0, a>0, then the area of the region R=\(x,y) 0 y f(ax), 0 x 2\ is :

  1. e2-1
  2. e4+1
  3. e2+1
  4. e4-1

All Application of Integrals PYQs →

PDFDownload Application of Integrals PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters