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Application of Integrals

JEE Main 2025 (Online) 3rd April Evening ShiftMCQMedium📈 Topic in 71% papers+4−1
Ques. 1JEE Main 2025, 3 April (Evening Shift)

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243

Answer

(4) 10243

Solution

|x - y| y -y x - y y 0 x 2y

region: x2 y 4 x, x 0

Intersection of y = x2 and y = 4 x:

x2 = 4 x x = 8 x = 64 (or x = 0)

A = 064 (4 x - x2 ) dx

= [ 83x3/2 - x24 ]064

= 83(512) - 40964

= 40963 - 1024 = 10243

Answer: (4)

Keep practising — Application of Integrals

Ques. 2JEE Main 2025, 2 April (Morning Shift)

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

Ques. 3JEE Main 2025, 29 January (Morning Shift)

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
Ques. 4JEE Main 2025, 29 January (Evening Shift)

Let the area enclosed between the curves |y|=1-x2 and x2+y2=1 be . If 9 = + ; , are integers, then the value of | - | equals:

  1. 15
  2. 18
  3. 33
  4. 27
Ques. 5JEE Main 2025, 28 January (Morning Shift)

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
Ques. 6JEE Main 2025, 28 January (Evening Shift)

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
Ques. 7JEE Main 2025, 24 January (Morning Shift)

The area of the region \(x,y):x2+4x+2 y |x+2| \ is equal to

  1. 7
  2. 24/5
  3. 20/3
  4. 5
Ques. 8JEE Main 2025, 24 January (Evening Shift)

The area of the region enclosed by the curves y=ex, y=|ex-1| and y-axis is :

  1. 1+ e2
  2. e2
  3. 1- e2
  4. 2 e2-1
Ques. 9JEE Main 2025, 23 January (Morning Shift)

If the area of the larger portion bounded between the curves x2+y2=25 and y=|x-1| is 14(b +c), b,c , then b+c is equal to

Ques. 10JEE Main 2025, 23 January (Evening Shift)

If the area of the region \(x,y):-1 x 1, 0 y a+e|x|-e-x, a>0 \ is e2+8e+1e, then the value of a is :

  1. 7
  2. 5
  3. 6
  4. 8
Ques. 11JEE Main 2025, 22 January (Morning Shift)

The area of the region, inside the circle (x-2 3)2+y2=12 and outside the parabola y2=2 3 x is :

  1. 3 -8
  2. 6 -8
  3. 3 +8
  4. 6 -16

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