Let the line passing through the point (-1,2,1) and parallel to the line x-12= y+13= z4 intersect the line x+23= y-32= z-41 at the point P. Then the distance of P from the point Q(4,-5,1) is
- 5 6
- 5
- 5 5
- 10
Answer
(3) 5 5
Solution
Meet the two lines at P:
[figure]
1: (2 -1, 3 +2, 4 +1); 2: (3 -2, 2 +3, +4)
Equate x,y: 2 -1=3 -2, 3 +2=2 +3 = =1 (z: 5=5 ✓)
P=(1,5,5) PQ= 32+102+42= 125=5 5
Answer: (3)