The perpendicular distance, of the line x-12= y+2-1= z+32 from the point P(2,-10,1), is :
- 6
- 4 3
- 3 5
- 5 2
Answer
(3) 3 5
Solution
A=(1,-2,-3), d=(2,-1,2), | d|=3, AP=(1,-8,4)
[figure]
AP2=81; AF = projection of AP on d = 2+8+83=6
PF= 81-36=3 5 (right angle at F)
Answer: (3)