Let y=y(x) be the solution of the differential equation x 1-x2 dy+ (y 1-x2-x -1x )dx=0, x (0, 1), x 1-y(x)=1. Then y ( 12 ) equals :
- 3- 3
- 4- 3
- 4- 2 3
- 3- 2 3
Answer
(1) 3- 3
Solution
x 1 - x2 dy + y 1 - x2 dx = x -1x dx
1 - x2 (x dy + y dx) = x -1x dx d(xy) = x -1x 1 - x2 dx
Integrating by parts ( -1x first, x 1 - x2dx = - 1 - x2):
x -1x 1 - x2dx = - 1 - x2 -1x - 1 - x2 1 1 - x2 dx = - 1 - x2 -1x - x + C
xy = - 1 - x2 -1x - x + C
As x 1-, y 1, so 1 = 0 - 1 + C and C = 2.
At x = 12: y2 = - 32 3 - 12 + 2 = 32 - 2 3
y ( 12 ) = 3 - 3
Answer: (1)