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Matrices

JEE Main 2025 (Online) 29th January Morning ShiftNumericalMedium📈 Topic in 32% papers+4
Ques. 1JEE Main 2025, 29 January (Morning Shift)

Let S = \m Z : Am2 + Am = 3I - A-6 \, where A = bmatrix 2 & -1 \ 1 & 0 bmatrix. Then n(S) is equal to .

Answer

2

Solution

Let N = A - I = bmatrix 1 & -1 \ 1 & -1 bmatrix

N2 = bmatrix 1 - 1 & -1 + 1 \ 1 - 1 & -1 + 1 bmatrix = O

Ak = (I + N)k = I + kN for k N (binomial expansion, N2 = O)

Also (I + N)(I - N) = I - N2 = I A-1 = I - N, so Ak = I + kN for every integer k

Am2 + Am = 2I + (m2 + m)N

3I - A-6 = 3I - (I - 6N) = 2I + 6N

N O m2 + m = 6 (m + 3)(m - 2) = 0

m = 2 or m = -3

n(S) = 2

Answer: 2

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Ques. 2JEE Main 2025, 29 January (Evening Shift)

Let A = [aij] be a matrix of order 3 3, with aij = ( 2)i+j. If the sum of all the elements in the third row of A2 is + 2, , Z, then + is equal to :

  1. 210
  2. 280
  3. 224
  4. 168
Ques. 3JEE Main 2025, 28 January (Morning Shift)

Let M denote the set of all real matrices of order 3 3 and let S = \-3, -2, -1, 1, 2\. Let S1 = \A = [aij] M : A = AT and aij S, i, j\, S2 = \A = [aij] M : A = -AT and aij S, i, j\, S3 = \A = [aij] M : a11 + a22 + a33 = 0 and aij S, i, j\. If n(S1 S2 S3) = 125 , then equals .

Ques. 4JEE Main 2025, 28 January (Evening Shift)

Let A = bmatrix 1 2 & -2 \ 0 & 1 bmatrix and P = bmatrix & - \ & bmatrix, > 0. If B = PAP , C = P B10P and the sum of the diagonal elements of C is mn, where (m, n) = 1, then m + n is :

  1. 127
  2. 2049
  3. 258
  4. 65
Ques. 5JEE Main 2025, 24 January (Morning Shift)

Let A be a 3 3 matrix such that XTAX=O for all nonzero 3 1 matrices X= bmatrixx\ \ bmatrix. If A bmatrix1\\1\\1 bmatrix= bmatrix1\\4\\-5 bmatrix, A bmatrix1\\2\\1 bmatrix= bmatrix0\\4\\-8 bmatrix, and (adj(2(A+I)))=2 3 5 , , , N, then 2+ 2+ 2 is

Ques. 6JEE Main 2025, 24 January (Evening Shift)

Let A=[aij] be a square matrix of order 2 with entries either 0 or 1. Let E be the event that A is an invertible matrix. Then the probability P(E) is :

  1. 38
  2. 18
  3. 316
  4. 58
Ques. 7JEE Main 2025, 23 January (Evening Shift)

Let A=[aij] be a 3 3 matrix such that A bmatrix0\\1\\0 bmatrix= bmatrix0\\0\\1 bmatrix, A bmatrix4\\1\\3 bmatrix= bmatrix0\\1\\0 bmatrix and A bmatrix2\\1\\2 bmatrix= bmatrix1\\0\\0 bmatrix, then a23 equals :

  1. 2
  2. -1
  3. 1
  4. 0

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