In the hydrocarbon, 6CH3- 5CH= 4CH- 3CH2- 2C 1CH The states of hybridization of carbons 1, 3 and 5 are in the following sequence
- sp, sp2, sp3
- sp3, sp2, sp
- sp2, sp, sp3
- sp, sp3, sp2
Answer
(4) sp, sp3, sp2
Solution
As per NCERT, a carbon with only single bonds is sp3, a carbon with one double bond is sp2 and a carbon with a triple bond is sp hybridised.
So C-1 ( CH), with a triple bond, is sp; C-3 (-CH2-), with only single bonds, is sp3; and C-5 (=CH-), with a double bond, is sp2.
Sequence: sp, sp3, sp2
Answer: (4)