The number of ways, of forming a queue of 4 boys and 3 girls such that all the girls are not together, is:
(4) 4320
Total arrangements of 7 persons =7!=5040
All 3 girls together: treat them as one unit 5 units, 5! ways, girls among themselves 3! ways
5! 3!=120 6=720
All girls not together =5040-720=4320
Answer: (4)
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