Let pn denote the total number of triangles formed by joining the vertices of an n-side regular polygon. If pn+1-pn=66, then the sum of all distinct prime divisors of n is :
- 7
- 8
- 5
- 6
Answer
(3) 5
Solution
No three vertices of a regular polygon are collinear, so pn = nC3 and
pn + 1 - pn = n + 1C3 - nC3 = nC2
n(n - 1)2 = 66 n2 - n - 132 = 0
(n - 12)(n + 11) = 0 n = 12
Since 12 = 22 3, the distinct prime divisors are 2 and 3.
Sum = 2 + 3 = 5
Answer: (3)