Let A= bmatrix1 & 1 & 2\ -2 & 0 & 1\ 1 & 3 & 5 bmatrix. Then the sum of all elements of the matrix adj (adj (2(adj A)-1 ) ) is equal to:
- 3
- 4
- -4
- -3
Answer
(4) -3
Solution
|A| = 1(0 - 3) - 1(-10 - 1) + 2(-6 - 0) = -3 + 11 - 12 = -4
adj A = |A|A-1, (adj A)-1 = A|A| = - A4.
Let B = 2(adj A)-1 = - A2, so
|B| = (- 12 )3|A| = - 18(-4) = 12
For a 3 3 matrix, adj(adj B) = |B|3 - 2B = |B| B, hence
adj(adj B) = 12 (- A2 ) = - A4
The sum of the elements of A is 1 + 1 + 2 - 2 + 0 + 1 + 1 + 3 + 5 = 12.
Required sum = - 124 = -3
Answer: (4)