Let A be a 3 3 matrix such that A + AT = O. If A bmatrix 1 \ -1 \ 0 bmatrix = bmatrix 3 \ 3 \ 2 bmatrix, A2 bmatrix 1 \ -1 \ 0 bmatrix = bmatrix -3 \ 19 \ -24 bmatrix and (adj(2 adj(A + I))) = (2) (3) (11) , , , are non-negative integers, then + + is equal to
Answer
18
Solution
A is skew-symmetric, so let A = bmatrix 0 & p & q \ -p & 0 & r \ -q & -r & 0 bmatrix. Then
A bmatrix 1 \ -1 \ 0 bmatrix = bmatrix -p \ -p \ r - q bmatrix = bmatrix 3 \ 3 \ 2 bmatrix
p = -3, r - q = 2
Next,
A2 bmatrix 1 \ -1 \ 0 bmatrix = A bmatrix 3 \ 3 \ 2 bmatrix = bmatrix 3p + 2q \ -3p + 2r \ -3q - 3r bmatrix = bmatrix -3 \ 19 \ -24 bmatrix
which gives -9 + 2q = -3, so q = 3, and 9 + 2r = 19, so r = 5 (check: -3(3 + 5) = -24). Hence
A + I = bmatrix 1 & -3 & 3 \ 3 & 1 & 5 \ -3 & -5 & 1 bmatrix
|A + I| = 1(1 + 25) + 3(3 + 15) + 3(-15 + 3) = 26 + 54 - 36 = 44
For a matrix M of order 3, |adj M| = |M|2 and |kM| = k3|M|. Let B = 2 adj(A + I); then |B| = 23 442, so
|adj B| = |B|2 = 26 444 = 26 28 114 = 214 30 114
Thus = 14, = 0 and = 4.
+ + = 18
Answer: 18