If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by 0.5\%. The initial momentum of electron will be
- 200 P
- 400 P
- P200
- 100 P
Answer
(1) 200 P
Solution
The de Broglie wavelength is = hp, so | | = pp.
Here = 0.5\% = 1200 and p = P, so
Pp = 1200
∴ p = 200 P
Answer: (1)