Let y2=12x be the parabola and S be its focus. Let PQ be a focal chord of the parabola such that (SP)(SQ)= 1474. Let C be the circle described taking PQ as a diameter. If the equation of a circle C is 64x2+64y2- x-64 3 y= , then - is equal to .
Answer
1328
Solution
For y2=12x, a=3 and the focus is S(3,0). Taking P(3t2,6t) and Q ( 3t2,- 6t ) as ends of a focal chord, SP SQ= 9(1+t2)2t2= 1474
⇒ 12t4-25t2+12=0 ⇒ t2= 34 or 43; the term -64 3y needs t=- 32, so
P ( 94,-3 3 ), Q(4,4 3)
[figure]
The circle on PQ as diameter is (x- 94 )(x-4)+(y+3 3)(y-4 3)=0 ⇒ 64x2+64y2-400x-64 3y=1728
∴ =400, =1728, so - =1328
Answer: 1328