The equation of the chord, of the ellipse x225+ y216=1, whose mid-point is (3,1) is :
- 5x+16y=31
- 48x+25y=169
- 4x+122y=134
- 25x+101y=176
Answer
(2) 48x+25y=169
Solution
The chord of x225+ y216=1 with mid-point (3,1) is given by T=S1:
[figure]
3x25+ y16= 925+ 116
Multiplying by 400,
48x+25y=144+25
48x+25y=169
Answer: (2)