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Hydrocarbons

AIPMT 2001MCQEasy📈 Topic in 62% papers+4−1
Ques. 1AIPMT 2001

Which alkene on ozonolysis gives CH3CH2CHO and CH3COCH3?

  1. [figure]
  2. CH3CH2CH=CHCH2CH3
  3. CH3CH2CH=CHCH3
  4. [figure]

Answer

(1) [figure]

Solution

On ozonolysis the C=C bond breaks and each carbon of the double bond becomes a C=O carbon.

To find the alkene, join the two carbonyl carbons by a double bond (removing both O atoms):

CH3CH2CH=O + O=C(CH3)2 CH3CH2CH=C(CH3)2

The alkene is 2-methylpent-2-ene, CH3CH2CH=C(CH3)2.

(2) gives only CH3CH2CHO; (3) gives CH3CH2CHO and CH3CHO; (4) gives CH3COCH3 and CH3CHO.

Answer: (1)

Keep practising — Hydrocarbons

Ques. 2AIPMT 2000

Increasing order of electrophilic substitution for following compounds [figure]

  1. IV < I < II < III
  2. III < II < I < IV
  3. I < IV < III < II
  4. II < III < I < IV
Ques. 3AIPMT 2000

In Friedel-Crafts reaction, toluene can be prepared by

  1. C6H6 + CH3Cl
  2. C6H5Cl + CH4
  3. C6H6 + CH2Cl2
  4. C6H6 + CH3COCl

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