Units and Measurements

The physical quantity that has the same dimensional formula as pressure is

1. Coefficient of viscosity
2. Force
3. Momentum
4. Young's modulus of elasticity

The percentage error in the measurement of g is : (Given that g = 4 2 LT2, L = (10 0.1) cm, T = (100 1) s)

1. 7%
2. 2%
3. 5%
4. 3%

If E and G respectively denote energy and gravitational constant, then EG has the dimensions of :

1. [M2] [L-2] [T-1]
2. [M2] [L-1] [T0]
3. [M] [L-1] [T-1]
4. [M] [L0] [T0]

A screw gauge gives the following readings when used to measure the diameter of a wire Main scale reading : 0 mm Circular scale reading : 52 divisions Given that 1 mm on main scale corresponds to 100 divisions on the circular scale. The diameter of the wire from the above data is :

1. 0.052 cm
2. 0.52 cm
3. 0.026 cm
4. 0.26 cm

If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.

1. [F] [A-1] [T]
2. [F] [A] [T]
3. [F] [A] [T2]
4. [F] [A] [T-1]

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :

1. 0.25 mm
2. 0.5 mm
3. 1.0 mm
4. 0.01 mm

Taking into account of the significant figures, what is the value of 9.99 m - 0.0099 m?

1. 9.98 m
2. 9.980 m
3. 9.9 m
4. 9.9801 m

Dimensions of stress are :

1. [ ML2T-2]
2. [ ML0T-2]
3. [ ML-1T-2]
4. [ MLT-2]

In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where X = A2B1/2 C1/3D3, will be :

1. 16%
2. -10\%
3. 10%
4. ( 313 )\%

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is

1. 0.521 cm
2. 0.525 cm
3. 0.053 cm
4. 0.529 cm