Amines

The correct statement regarding the basicity of arylamines is

1. arylamines are generally more basic than alkylamines because of aryl group
2. arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridised
3. arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring -electron system
4. arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring -electron system.

Which one of the following nitro-compounds does not react with nitrous acid?

1. [figure]
2. [figure]
3. [figure]
4. [figure]

A given nitrogen-containing aromatic compound 'A' reacts with Sn/HCl, followed by HNO2 to give an unstable compound 'B'. 'B', on treatment with phenol, forms a beautiful coloured compound 'C' with the molecular formula C12H10N2O. The structure of compound 'A' is

1. [figure]
2. [figure]
3. [figure]
4. [figure]

The following reaction [figure] is known by the name

1. Perkin's reaction
2. Acetylation reaction
3. Schotten-Baumann reaction
4. Friedel-Craft's reaction

Method by which aniline cannot be prepared is

1. degradation of benzamide with bromine in alkaline solution
2. reduction of nitrobenzene with H2/Pd in ethanol
3. potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
4. hydrolysis of phenylisocyanide with acidic solution.

The electrolytic reduction of nitrobenzene in strongly acidic medium produces

1. azobenzene
2. aniline
3. p-aminophenol
4. azoxybenzene.

In the following reaction, the product (A) is [figure]

1. [figure]
2. [figure]
3. [figure]
4. [figure]

Which of the following will be most stable diazonium salt RN2+X-?

1. CH3N2+X-
2. C6H5N2+X-
3. CH3CH2N2+X-
4. C6H5CH2N2+X-

In the reaction [figure] A is

1. H3PO2 and H2O
2. H+/H2O
3. HgSO4/H2SO4
4. Cu2Cl2

On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The "compound" is

1. CH3CH2CH2NC
2. CH3CH2CH2CN
3. CH3CH2CH2ON=O
4. CH3CH2CH2CON(CH3)2