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Sequences and Series

JEE Main 2025 (Online) 23rd January Evening ShiftNumericalMedium📈 Topic in 57% papers+4
Ques. 1JEE Main 2025, 23 January (Evening Shift)

The roots of the quadratic equation 3x2-px+q=0 are 10th and 11th terms of an arithmetic progression with common difference 32. If the sum of the first 11 terms of this arithmetic progression is 88, then q-2p is equal to .

Answer

474

Solution

S11=11(a+5d)=88 a+5d=8, d= 32 a= 12

Roots: T10=14, T11= 312

p3= 592 p= 1772; q3=14 312=217 q=651

q-2p=651-177=474

Answer: 474

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Ques. 2JEE Main 2025, 22 January (Morning Shift)

Let a1,a2,a3, be a G.P. of increasing positive terms. If a1a5=28 and a2+a4=29, then a6 is equal to:

  1. 812
  2. 784
  3. 628
  4. 526
Ques. 3JEE Main 2025, 22 January (Morning Shift)

If r=1nTr= (2n-1)(2n+1)(2n+3)(2n+5)64, then n r=1n ( 1Tr ) is equal to :

  1. 23
  2. 13
  3. 1
  4. 0
Ques. 4JEE Main 2025, 22 January (Evening Shift)

Suppose that the number of terms in an A.P. is 2k, k . If the sum of all odd terms of the A.P. is 40, the sum of all even terms is 55 and the last term of the A.P. exceeds the first term by 27, then k is equal to:

  1. 8
  2. 6
  3. 4
  4. 5
Ques. 5JEE Main 2024, 9 April (Morning Shift)

If the sum of the series 11 (1 + d) + 1(1 + d)(1 + 2d) + + 1(1 + 9d)(1 + 10d) is equal to 5, then 50d is equal to :

  1. 5
  2. 10
  3. 15
  4. 20
Ques. 6JEE Main 2024, 9 April (Evening Shift)

Let a, ar, ar2, be an infinite G.P. If n=0 arn = 57 and n=0 a3r3n = 9747, then a + 18r is equal to

  1. 27
  2. 38
  3. 31
  4. 46
Ques. 7JEE Main 2024, 9 April (Evening Shift)

If ( 1 + 1 + 1 + 2 + + 1 + 1012 ) - ( 12 1 + 14 3 + 16 5 + + 12024 2023 ) = 12024, then is equal to .

Ques. 8JEE Main 2024, 8 April (Morning Shift)

Let the positive integers be written in the form : [figure] If the kth row contains exactly k numbers for every natural number k, then the row in which the number 5310 will be, is .

Ques. 9JEE Main 2024, 8 April (Evening Shift)

In an increasing geometric progression of positive terms, the sum of the second and sixth terms is 703 and the product of the third and fifth terms is 49. Then the sum of the 4th, 6th and 8th terms is equal to:

  1. 78
  2. 96
  3. 91
  4. 84
Ques. 10JEE Main 2024, 8 April (Evening Shift)

An arithmetic progression is written in the following way [figure] The sum of all the terms of the 10th row is .

Ques. 11JEE Main 2024, 6 April (Morning Shift)

Let the first term of a series be T1 = 6 and its rth term Tr = 3Tr-1 + 6r, r = 2, 3, , n. If the sum of the first n terms of this series is 15 (n2 - 12n + 39 ) (4 6n - 5 3n + 1 ), then n is equal to .

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