Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Sequences and Series

JEE Main 2024 (Online) 9th April Evening ShiftNumericalMedium📈 Topic in 22% papers+4
Ques. 1JEE Main 2024, 9 April (Evening Shift)

If ( 1 + 1 + 1 + 2 + + 1 + 1012 ) - ( 12 1 + 14 3 + 16 5 + + 12024 2023 ) = 12024, then is equal to .

Answer

1011

Solution

Since 12r(2r - 1) = 12r - 1 - 12r, the second bracket

= (1 - 12 ) + ( 13 - 14 ) + + ( 12023 - 12024 )

= (1 + 12 + + 12024 ) - 2 ( 12 + 14 + + 12024 )

= (1 + 12 + + 12024 ) - (1 + 12 + + 11012 )

= 11013 + 11014 + + 12024

So the first bracket = 11013 + + 12023 + 22024 = 11012 + 11013 + + 12023 (as 22024 = 11012)

Both sides have 1012 consecutive terms, so + 1 = 1012 = 1011 (the left side decreases as increases, so this is the only value).

Answer: 1011

Keep practising — Sequences and Series

Ques. 2JEE Main 2024, 8 April (Morning Shift)

Let the positive integers be written in the form : [figure] If the kth row contains exactly k numbers for every natural number k, then the row in which the number 5310 will be, is .

Ques. 3JEE Main 2024, 8 April (Evening Shift)

In an increasing geometric progression of positive terms, the sum of the second and sixth terms is 703 and the product of the third and fifth terms is 49. Then the sum of the 4th, 6th and 8th terms is equal to:

  1. 78
  2. 96
  3. 91
  4. 84
Ques. 4JEE Main 2024, 8 April (Evening Shift)

An arithmetic progression is written in the following way [figure] The sum of all the terms of the 10th row is .

Ques. 5JEE Main 2024, 6 April (Morning Shift)

Let the first term of a series be T1 = 6 and its rth term Tr = 3Tr-1 + 6r, r = 2, 3, , n. If the sum of the first n terms of this series is 15 (n2 - 12n + 39 ) (4 6n - 5 3n + 1 ), then n is equal to .

Ques. 6JEE Main 2024, 6 April (Evening Shift)

n (12 - 1)(n - 1) + (22 - 2)(n - 2) + + ((n - 1)2 - (n - 1)) 1(13 + 23 + + n3) - (12 + 22 + + n2) is equal to :

  1. 23
  2. 12
  3. 34
  4. 13
Ques. 7JEE Main 2024, 6 April (Evening Shift)

Let ABC be an equilateral triangle. A new triangle is formed by joining the middle points of all sides of the triangle ABC and the same process is repeated infinitely many times. If P is the sum of perimeters and Q is the sum of areas of all the triangles formed in this process, then :

  1. P2 = 72 3Q
  2. P2 = 36 3Q
  3. P = 36 3Q2
  4. P2 = 6 3Q
Ques. 8JEE Main 2024, 6 April (Evening Shift)

A software company sets up m number of computer systems to finish an assignment in 17 days. If 4 computer systems crashed on the start of the second day, 4 more computer systems crashed on the start of the third day and so on, then it took 8 more days to finish the assignment. The value of m is equal to:

  1. 125
  2. 160
  3. 150
  4. 180
Ques. 9JEE Main 2024, 6 April (Evening Shift)

If S(x) = (1 + x) + 2(1 + x)2 + 3(1 + x)3 + + 60(1 + x)60, x 0, and (60)2 S(60) = a(b)b + b, where a, b N, then (a + b) equal to .

Ques. 10JEE Main 2024, 5 April (Morning Shift)

If 1 1 + 2 + 1 2 + 3 + + 1 99 + 100 = m and 11 2 + 12 3 + + 199 100 = n, then the point (m, n) lies on the line

  1. 11(x - 1) - 100y = 0
  2. 11x - 100y = 0
  3. 11(x - 1) - 100(y - 2) = 0
  4. 11(x - 2) - 100(y - 1) = 0
Ques. 11JEE Main 2024, 5 April (Morning Shift)

Let a1, a2, a3, be in an arithmetic progression of positive terms. Let Ak = a12 - a22 + a32 - a42 + + a2k-12 - a2k2. If A3 = -153, A5 = -435 and a12 + a22 + a32 = 66, then a17 - A7 is equal to .

All Sequences and Series PYQs →

PDFDownload Sequences and Series PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters