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Structure of Atom

AIPMT 2004MCQEasyNot asked in last 5 yrs+4−1
Ques. 1AIPMT 2004

The radioactive isotope 6027Co which is used in the treatment of cancer can be made by (n, p) reaction. For this reaction the target nucleus is

  1. 5928Ni
  2. 5927Co
  3. 6028Ni
  4. 6027Co

Answer

(3) 6028Ni

Solution

In an (n, p) reaction the target nucleus absorbs a neutron 10n and emits a proton 11H:

AZX + 10n 6027Co + 11H

Mass numbers: A + 1 = 60 + 1, so A = 60

Atomic numbers: Z + 0 = 27 + 1, so Z = 28 (nickel)

Target nucleus = 6028Ni

Answer: (3)

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Ques. 2AIPMT 2003

The value of Planck's constant is 6.63 10-34 J s. The velocity of light is 3.0 108 m s-1. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8 1015 s-1 ?

  1. 2 10-25
  2. 5 10-18
  3. 4 101
  4. 3 107
Ques. 3AIPMT 2002

In hydrogen atom, energy of first excited state is -3.4 eV. Then find out K.E. of same orbit of hydrogen atom

  1. +3.4 eV
  2. +6.8 eV
  3. -13.6 eV
  4. +13.6 eV
Ques. 4AIPMT 2002

23592U, nucleus absorbs a neutron and disintegrates into 13954Xe, 9438Sr and x so, what will be product x?

  1. 3-neutrons
  2. 2-neutrons
  3. -particle
  4. -particle
Ques. 5AIPMT 2001

The following quantum numbers are possible for how many orbitals : n = 3, l = 2, m = +2 ?

  1. 1
  2. 2
  3. 3
  4. 4
Ques. 6AIPMT 2001

If a abX species emits first a positron, then two and two particles and in the last, one is also emitted and gets converted to cdY species. So correct relation is

  1. c = a - 12, d = b - 5
  2. c = a - 5, d = b - 1
  3. c = a - 6, d = b - 0
  4. c = a - 4, d = b - 2
Ques. 7AIPMT 2000

For given energy, E = 3.03 10-19 Joules corresponding wavelength is (h = 6.626 10-34 J sec, c = 3 108 m/sec)

  1. 65.6 nm
  2. 6.56 nm
  3. 3.4 nm
  4. 656 nm
Ques. 8AIPMT 2000

Isoelectronic species are

  1. CO, CN-, NO+, C22-
  2. CO-, CN, NO, C2-
  3. CO+, CN+, NO-, C2
  4. CO, CN, NO, C2

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