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Complex Numbers and Quadratic Equations

JEE Main 2025 (Online) 3rd April Morning ShiftMCQMedium📈 Topic in 34% papers+4−1
Ques. 1JEE Main 2025, 3 April (Morning Shift)

Let z C be such that z2+3iz-2+i = 2+3i. Then the sum of all possible values of z2 is :

  1. -19+2i
  2. -19-2i
  3. 19-2i
  4. 19+2i

Answer

(2) -19-2i

Solution

z2 + 3i = (2+3i)(z-2+i)

z2 + 3i = (2+3i)z + (2+3i)(-2+i)

Since (2+3i)(-2+i) = -4 + 2i - 6i + 3i2 = -7 - 4i,

z2 - (2+3i)z + (7+7i) = 0

Neither of its roots z1, z2 equals 2-i, so both are admissible, with

z1 + z2 = 2+3i, z1z2 = 7+7i

z12 + z22 = (z1+z2)2 - 2z1z2

= (2+3i)2 - 2(7+7i)

= (4 - 9 + 12i) - 14 - 14i

= -19 - 2i

Answer: (2)

Keep practising — Complex Numbers and Quadratic Equations

Ques. 2JEE Main 2025, 3 April (Evening Shift)

If z1, z2, z3 C are the vertices of an equilateral triangle whose centroid is z0, then k=13 (zk - z0)2 is equal to

  1. 0
  2. 1
  3. i
  4. -i
Ques. 3JEE Main 2025, 3 April (Evening Shift)

Let the equation x(x + 2)(12 - k) = 2 have equal roots. Then the distance of the point (k, k2 ) from the line 3x + 4y + 5 = 0 is

  1. 15
  2. 12
  3. 5 3
  4. 15 5
Ques. 4JEE Main 2025, 2 April (Morning Shift)

Let z be a complex number such that |z| = 1. If 2 + k2 zk + z = kz, k R, then the maximum distance of k + ik2 from the circle |z - (1 + 2i)| = 1 is :

  1. 5 + 1
  2. 3
  3. 3 + 1
  4. 2
Ques. 5JEE Main 2025, 2 April (Morning Shift)

Let Pn = n + n, n N. If P10 = 123, P9 = 76, P8 = 47 and P1 = 1, then the quadratic equation having roots 1 and 1 is :

  1. x2 + x - 1 = 0
  2. x2 - x + 1 = 0
  3. x2 + x + 1 = 0
  4. x2 - x - 1 = 0
Ques. 6JEE Main 2025, 2 April (Evening Shift)

If the set of all a R - \1\, for which the roots of the equation (1 - a)x2 + 2(a - 3)x + 9 = 0 are positive is (- , - ] [ , ), then 2 + + is equal to .

Ques. 7JEE Main 2025, 29 January (Morning Shift)

The number of solutions of the equation ( 9x - 9 x + 2 ) ( 2x - 7 x + 3 ) = 0 is :

  1. 3
  2. 2
  3. 1
  4. 4
Ques. 8JEE Main 2025, 29 January (Morning Shift)

Let |z1 - 8 - 2i| 1 and |z2 - 2 + 6i| 2, z1, z2 C. Then the minimum value of |z1 - z2| is :

  1. 3
  2. 10
  3. 7
  4. 13
Ques. 9JEE Main 2025, 29 January (Evening Shift)

If the set of all a R, for which the equation 2x2 + (a - 5)x + 15 = 3a has no real root, is the interval ( , ), and X = \x Z; < x < \, then x X x2 is equal to:

  1. 2139
  2. 2119
  3. 2109
  4. 2129
Ques. 10JEE Main 2025, 29 January (Evening Shift)

Let integers a, b [-3,3] be such that a+b 0. Then the number of all possible ordered pairs (a, b), for which | z-az+b |=1 and vmatrixz+1& & 2\ &z+ 2&1\ 2&1&z+ vmatrix=1, z C, where and 2 are the roots of x2+x+1=0, is equal to .

Ques. 11JEE Main 2025, 28 January (Morning Shift)

The sum, of the squares of all the roots of the equation x2 + |2x - 3| - 4 = 0, is

  1. 6(2 - 2)
  2. 3(3 - 2)
  3. 3(2 - 2)
  4. 6(3 - 2)

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