Let |z1 - 8 - 2i| 1 and |z2 - 2 + 6i| 2, z1, z2 C. Then the minimum value of |z1 - z2| is :
(3) 7
z1 lies in the disc with centre C1(8, 2), radius r1 = 1.
z2 lies in the disc with centre C2(2, -6), radius r2 = 2.
C1C2 = (8 - 2)2 + (2 + 6)2 = 36 + 64 = 10
C1C2 > r1 + r2, the discs do not meet.
|z1 - z2| = C1C2 - r1 - r2 = 10 - 3 = 7
Answer: (3)
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