Let S=\z C : z2+4z+16=0\. Then z S |z+ 3 i |2 is equal to :
- 42
- 23
- 27
- 38
Answer
(4) 38
Solution
Solving the quadratic,
z2 + 4z + 16 = 0 z = -4 16 - 642 = -2 2 3 i
For z1 = -2 + 2 3 i, z1 + 3 i = -2 + 3 3 i, so |z1 + 3 i |2 = 4 + 27 = 31.
For z2 = -2 - 2 3 i, z2 + 3 i = -2 - 3 i, so |z2 + 3 i |2 = 4 + 3 = 7.
∴ z S |z + 3 i |2 = 31 + 7 = 38
Answer: (4)