Pick out the correct statement with respect to [Mn(CN)6]3-.
- It is sp3d2 hybridised and tetrahedral.
- It is d2sp3 hybridised and octahedral.
- It is dsp2 hybridised and square planar.
- It is sp3d2 hybridised and octahedral.
Answer
(2) It is d2sp3 hybridised and octahedral.
Solution
In [Mn(CN)6]3- the oxidation state of Mn is +3, so Mn3+ is [Ar] 3d4.
CN- is a strong field ligand, the four 3d electrons pair up in three 3d orbitals, leaving two 3d orbitals vacant. Two 3d, one 4s and three 4p orbitals then hybridise to give d2sp3 (inner orbital complex), so the six CN- ligands are arranged octahedrally, and the complex has 2 unpaired electrons (paramagnetic).
As per NCERT, [Mn(CN)6]3- is an inner orbital, d2sp3 hybridised, octahedral complex.
Answer: (2)