Let the set of all values of r, for which the circles (x+1)2 + (y+4)2 = r2 and x2 + y2 - 4x - 2y - 4 = 0 intersect at two distinct points be the interval ( , ). Then is equal to
- 21
- 24
- 20
- 25
Answer
(4) 25
Solution
Circle 1 has centre C1(-1, -4) and radius r; circle 2 has centre C2(2, 1) and radius 4 + 1 + 4 = 3.
C1C2 = (2+1)2 + (1+4)2 = 34
For two distinct points of intersection,
|r - 3| < 34 < r + 3
34 - 3 < r < 34 + 3
so = 34 - 3 and = 34 + 3.
= 34 - 9 = 25
Answer: (4)