Let the locus of the mid-point of the chord through the origin O of the parabola y2 = 4x be the curve S. Let P be any point on S. Then the locus of the point, which internally divides OP in the ratio 3 : 1, is :
- 2x2 = 3y
- 2y2 = 3x
- 3y2 = 2x
- 3x2 = 2y
Answer
(2) 2y2 = 3x
Solution
Any chord through O(0, 0) meets the parabola again at (t2, 2t), so its mid-point is h = t22, k = t. Eliminating t,
k2 = 2h, so S : y2 = 2x
Let P( , ) lie on S, so 2 = 2 . The point dividing OP internally in 3 : 1 is X = 3 4, Y = 3 4, so
= 4X3, = 4Y3
16Y29 = 8X3
2Y2 = 3X
Locus: 2y2 = 3x
Answer: (2)