Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Integrals

JEE Main 2025 (Online) 24th January Evening ShiftNumericalHard📈 Topic in 3% papers+4
Ques. 1JEE Main 2025, 24 January (Evening Shift)

If 2x2+5x+9 x2+x+1 dx =x x2+x+1+ x2+x+1 + e |x+ 12+ x2+x+1 |+C, where C is the constant of integration, then +2 is equal to .

Answer

16

Solution

Differentiate the right side and compare with the integrand; let S= x2+x+1.

ddx(xS)= 4x2+3x+22S, ddx( S)= (2x+1)2S, ddx [ (x+ 12+S ) ]= 2 2S

Sum = 4x2+(3+2 )x+(2+ +2 )2S= 4x2+10x+182S

3+2 =10 = 72

Constants: 2+ +2 =18

+2 =16

Answer: 16

Keep practising — Integrals

Ques. 2JEE Main 2025, 23 January (Morning Shift)

The value of e2e4 1x ( e (( ex)2+1 )-1e (( ex)2+1 )-1+e ((6- ex)2+1 )-1 )dx is

  1. 1
  2. loge 2
  3. e2
  4. 2
Ques. 3JEE Main 2025, 23 January (Morning Shift)

Let I(x)= dx(x-11) 1113(x+15) 1513. If I(37)-I(24)= 14 ( 1b 113- 1c 113 ), b,c N, then 3(b+c) is equal to

  1. 39
  2. 22
  3. 40
  4. 26
Ques. 4JEE Main 2025, 23 January (Evening Shift)

If I= 0 2 32x 32x+ 32x dx, then 02I x x x 4x+ 4x dx equals :

  1. 212
  2. 24
  3. 216
  4. 28
Ques. 5JEE Main 2025, 23 January (Evening Shift)

Let x3 x dx=g(x)+C, where C is the constant of integration. If 8 (g ( 2 )+g' ( 2 ) )= 3+ 2+ , , , Z, then + - equals :

  1. 47
  2. 55
  3. 62
  4. 48
Ques. 6JEE Main 2025, 22 January (Morning Shift)

Let for f(x)=7 8x+7 6x-3 4x-3 2x, I1= 0 /4f(x) dx and I2= 0 /4x f(x) dx. Then 7I1+12I2 is equal to :

  1. 2
  2. 1
  3. 2
Ques. 7JEE Main 2025, 22 January (Evening Shift)

If x ( x -1x 1-x2+ -1x(1-x2)3/2+ x1-x2 )dx=g(x)+C, where C is the constant of integration, then g ( 12 ) equals :

  1. 6 e3
  2. 6 e2
  3. 4 e3
  4. 4 e2
Ques. 8JEE Main 2024, 9 April (Morning Shift)

Let 2 - x3 + x dx = 12 ( x + e| x + x| ) + C, where C is the constant of integration. Then + is equal to :

  1. 3
  2. 7
  3. 1
  4. 4
Ques. 9JEE Main 2024, 9 April (Morning Shift)

Let n ( n n4 + 1 - 2n (n2 + 1 ) n4 + 1 . . + n n4 + 16 - 8n (n2 + 4 ) n4 + 16 + . . + n n4 + n4 - 2n n2 (n2 + n2 ) n4 + n4 ) be k, using only the principal values of the inverse trigonometric functions. Then k2 is equal to .

Ques. 10JEE Main 2024, 9 April (Evening Shift)

The integral 1/43/4 (2 -1 1 - x1 + x ) dx is equal to

  1. -1/2
  2. -1/4
  3. 1/4
  4. 1/2
Ques. 11JEE Main 2024, 9 April (Evening Shift)

x 2 ( x3( /2)3 ( (2t1/3 ) + (t1/3 ) ) dt (x - 2 )2 ) is equal to

  1. 3 22
  2. 9 28
  3. 5 29
  4. 11 210

All Integrals PYQs →

PDFDownload Integrals PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters