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Integrals

JEE Main 2025 (Online) 23rd January Evening ShiftMCQMedium📈 Topic in 67% papers+4−1
Ques. 1JEE Main 2025, 23 January (Evening Shift)

If I= 0 2 32x 32x+ 32x dx, then 02I x x x 4x+ 4x dx equals :

  1. 212
  2. 24
  3. 216
  4. 28

Answer

(3) 216

Solution

King's property: x 2-x in I and add 2I= 0 /2dx= 2, so the limits are 0 to 2.

J= 0 /2 x x x 4x+ 4xdx; same property: 2J= 2 0 /2 x x 4x+ 4xdx

Divide by 4x, put t= 2x, dt=2 x 2x dx:

J= 4 12 0 dt1+t2= 8 2

J= 216

Answer: (3)

Keep practising — Integrals

Ques. 2JEE Main 2025, 23 January (Evening Shift)

Let x3 x dx=g(x)+C, where C is the constant of integration. If 8 (g ( 2 )+g' ( 2 ) )= 3+ 2+ , , , Z, then + - equals :

  1. 47
  2. 55
  3. 62
  4. 48
Ques. 3JEE Main 2025, 22 January (Morning Shift)

Let for f(x)=7 8x+7 6x-3 4x-3 2x, I1= 0 /4f(x) dx and I2= 0 /4x f(x) dx. Then 7I1+12I2 is equal to :

  1. 2
  2. 1
  3. 2
Ques. 4JEE Main 2025, 22 January (Evening Shift)

If x ( x -1x 1-x2+ -1x(1-x2)3/2+ x1-x2 )dx=g(x)+C, where C is the constant of integration, then g ( 12 ) equals :

  1. 6 e3
  2. 6 e2
  3. 4 e3
  4. 4 e2
Ques. 5JEE Main 2024, 9 April (Morning Shift)

Let 2 - x3 + x dx = 12 ( x + e| x + x| ) + C, where C is the constant of integration. Then + is equal to :

  1. 3
  2. 7
  3. 1
  4. 4
Ques. 6JEE Main 2024, 9 April (Morning Shift)

Let n ( n n4 + 1 - 2n (n2 + 1 ) n4 + 1 . . + n n4 + 16 - 8n (n2 + 4 ) n4 + 16 + . . + n n4 + n4 - 2n n2 (n2 + n2 ) n4 + n4 ) be k, using only the principal values of the inverse trigonometric functions. Then k2 is equal to .

Ques. 7JEE Main 2024, 9 April (Evening Shift)

The integral 1/43/4 (2 -1 1 - x1 + x ) dx is equal to

  1. -1/2
  2. -1/4
  3. 1/4
  4. 1/2
Ques. 8JEE Main 2024, 9 April (Evening Shift)

x 2 ( x3( /2)3 ( (2t1/3 ) + (t1/3 ) ) dt (x - 2 )2 ) is equal to

  1. 3 22
  2. 9 28
  3. 5 29
  4. 11 210
Ques. 9JEE Main 2024, 9 April (Evening Shift)

The value of the integral -12 e (x + x2 + 1 ) dx is

  1. 5 - 2 + e ( 7 + 4 51 + 2 )
  2. 2 - 5 + e ( 7 + 4 51 + 2 )
  3. 5 - 2 + e ( 9 + 4 51 + 2 )
  4. 2 - 5 + e ( 9 + 4 51 + 2 )
Ques. 10JEE Main 2024, 8 April (Morning Shift)

The value of k N for which the integral In = 01 (1 - xk )n dx, n N, satisfies 147 I20 = 148 I21 is

  1. 8
  2. 14
  3. 7
  4. 10
Ques. 11JEE Main 2024, 8 April (Morning Shift)

Let I(x) = 6 2 x(1 - x)2 dx. If I(0) = 3, then I ( 12 ) is equal to

  1. 3
  2. 2 3
  3. 6 3
  4. 3 3

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