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Permutations and Combinations

JEE Main 2025 (Online) 28th January Morning ShiftMCQMedium📈 Topic in 12% papers+4−1
Ques. 1JEE Main 2025, 28 January (Morning Shift)

The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, such that the sum of their first and last digits should not be more than 8, is

  1. 5720
  2. 5719
  3. 4608
  4. 4607

Answer

(4) 4607

Solution

Digits may repeat. A 5 digit number greater than 50000 must begin with 5, 6 or 7.

(First digit + last digit) ≤ 8:

First digit 5 ⇒ last digit 0, 1, 2, 3 ⇒ 4 ways

First digit 6 ⇒ last digit 0, 1, 2 ⇒ 3 ways

First digit 7 ⇒ last digit 0, 1 ⇒ 2 ways

(first, last) pairs = 4 + 3 + 2 = 9

Each of the three middle places can be filled in 8 ways 83 = 512

Total = 9 512 = 4608

This count includes 50000, which is not greater than 50000.

Required number = 4608 - 1 = 4607

Answer: (4)

Keep practising — Permutations and Combinations

Ques. 2JEE Main 2025, 28 January (Evening Shift)

The number of natural numbers, between 212 and 999, such that the sum of their digits is 15, is .

Ques. 3JEE Main 2025, 24 January (Morning Shift)

Let S=\p1,p2 ,p10\ be the set of first ten prime numbers. Let A=S P, where P is the set of all possible products of distinct elements of S. Then the number of all ordered pairs (x,y), x S, y A, such that x divides y, is .

Ques. 4JEE Main 2025, 24 January (Morning Shift)

The number of 3-digit numbers, that are divisible by 2 and 3, but not divisible by 4 and 9, is .

Ques. 5JEE Main 2025, 24 January (Evening Shift)

Group A consists of 7 boys and 3 girls, while group B consists of 6 boys and 5 girls. The number of ways, 4 boys and 4 girls can be invited for a picnic if 5 of them must be from group A and the remaining 3 from group B, is equal to :

  1. 8925
  2. 9100
  3. 8575
  4. 8750
Ques. 6JEE Main 2025, 23 January (Morning Shift)

The number of words, which can be formed using all the letters of the word "DAUGHTER", so that all the vowels never come together, is :

  1. 34000
  2. 37000
  3. 35000
  4. 36000
Ques. 7JEE Main 2025, 23 January (Evening Shift)

The number of ways, 5 boys and 4 girls can sit in a row so that either all the boys sit together or no two boys sit together, is .

Ques. 8JEE Main 2025, 22 January (Morning Shift)

From all the English alphabets, five letters are chosen and are arranged in alphabetical order. The total number of ways, in which the middle letter is ' M ', is :

  1. 6084
  2. 5148
  3. 14950
  4. 4356
Ques. 9JEE Main 2025, 22 January (Evening Shift)

In a group of 3 girls and 4 boys, there are two boys B1 and B2. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but B1 and B2 are not adjacent to each other, is :

  1. 120
  2. 96
  3. 72
  4. 144
Ques. 10JEE Main 2024, 9 April (Evening Shift)

The number of integers, between 100 and 1000 having the sum of their digits equal to 14, is .

Ques. 11JEE Main 2024, 8 April (Morning Shift)

The number of 3-digit numbers, formed using the digits 2, 3, 4, 5 and 7, when the repetition of digits is not allowed, and which are not divisible by 3 , is equal to .

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