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Permutations and Combinations

JEE Main 2025 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 26% papers+4−1
Ques. 1JEE Main 2025, 24 January (Evening Shift)

Group A consists of 7 boys and 3 girls, while group B consists of 6 boys and 5 girls. The number of ways, 4 boys and 4 girls can be invited for a picnic if 5 of them must be from group A and the remaining 3 from group B, is equal to :

  1. 8925
  2. 9100
  3. 8575
  4. 8750

Answer

(1) 8925

Solution

Let A give x boys, y girls (x+y=5); then B gives 4-x boys and 4-y girls.

A has only 3 girls and 4-x 0 (x,y)=(2,3),(3,2),(4,1)

(2B, 3G): 7 C2 3 C3 6 C2 5 C1=21 1 15 5=1575

(3B, 2G): 7 C3 3 C2 6 C1 5 C2=35 3 6 10=6300

(4B, 1G): 7 C4 3 C1 6 C0 5 C3=35 3 1 10=1050

Total =1575+6300+1050=8925

Answer: (1)

Keep practising — Permutations and Combinations

Ques. 2JEE Main 2025, 23 January (Morning Shift)

The number of words, which can be formed using all the letters of the word "DAUGHTER", so that all the vowels never come together, is :

  1. 34000
  2. 37000
  3. 35000
  4. 36000
Ques. 3JEE Main 2025, 23 January (Evening Shift)

The number of ways, 5 boys and 4 girls can sit in a row so that either all the boys sit together or no two boys sit together, is .

Ques. 4JEE Main 2025, 22 January (Morning Shift)

From all the English alphabets, five letters are chosen and are arranged in alphabetical order. The total number of ways, in which the middle letter is ' M ', is :

  1. 6084
  2. 5148
  3. 14950
  4. 4356
Ques. 5JEE Main 2025, 22 January (Evening Shift)

In a group of 3 girls and 4 boys, there are two boys B1 and B2. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but B1 and B2 are not adjacent to each other, is :

  1. 120
  2. 96
  3. 72
  4. 144

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