Ratio of longest wave lengths corresponding to Lyman and Balmer series in hydrogen spectrum is
(3) 527
Longest wavelength = smallest energy transition of the series.
Lyman (n = 2 1): 1 L = R ( 112 - 122 ) = 3R4
Balmer (n = 3 2): 1 B = R ( 122 - 132 ) = 5R36
⇒ L B = 5R/363R/4 = 536 43
∴ L B = 527
Answer: (3)
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