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p-Block Elements (Group 13 & 14)

AIPMT 2009MCQEasy📈 Topic in 38% papers+4−1
Ques. 1AIPMT 2009

The straight chain polymer is formed by

  1. hydrolysis of CH3SiCl3 followed by condensation polymerisation
  2. hydrolysis of (CH3)4Si by addition polymerisation
  3. hydrolysis of (CH3)2SiCl2 followed by condensation polymerisation
  4. hydrolysis of (CH3)3SiCl followed by condensation polymerisation

Answer

(3) hydrolysis of (CH3)2SiCl2 followed by condensation polymerisation

Solution

As per NCERT, hydrolysis of dimethyldichlorosilane gives a silanediol with two –OH groups:

(CH3)2SiCl2 + 2H2O (CH3)2Si(OH)2 + 2HCl

each unit has two reactive –OH groups, so condensation polymerisation links them end to end into a straight chain silicone, –[–O–Si(CH3)2–]n–.

CH3SiCl3 gives three –OH groups (cross-linked polymer) and (CH3)3SiCl gives only one –OH group (chain stopper, dimer only).

Answer: (3)

Keep practising — p-Block Elements (Group 13 & 14)

Ques. 2AIPMT 2007

Which of the following oxidation states are the most characteristic for lead and tin respectively?

  1. +2, +4
  2. +4, +4
  3. +2, +2
  4. +4, +2
Ques. 3AIPMT 2007

Which of the following anions is present in the chain structure of silicates?

  1. (Si2O52-)n
  2. (SiO32-)n
  3. SiO44-
  4. Si2O76-
Ques. 4AIPMT 2004

Which one of the following statements about the zeolite is false?

  1. They are used as cation exchangers.
  2. They have open structure which enables them to take up small molecules.
  3. Zeolites are aluminosilicates having three dimensional network.
  4. Some of the SiO44- units are replaced by AlO45- and AlO69- ions in zeolites.
Ques. 5AIPMT 2003

Which one of the following compounds is not a protonic acid?

  1. B(OH)3
  2. PO(OH)3
  3. SO(OH)2
  4. SO2(OH)2
Ques. 6AIPMT 2001

PbO2 PbO; G298 < 0 SnO2 SnO; G298 > 0 Most probable oxidation state of Pb and Sn will be

  1. Pb4+, Sn4+
  2. Pb4+, Sn2+
  3. Pb2+, Sn2+
  4. Pb2+, Sn4+
Ques. 7AIPMT 2000

Which compound is electron deficient?

  1. PCl3
  2. BCl3
  3. CCl4
  4. PCl5

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