The distance of the line x-22= y-63= z-34 from the point (1,4,0) along the line x1= y-22= z+33 is :
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Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 32 | 19 | 1.7 | 6.74% ▼ 3% vs last year |
| 2025 | 33 | 19 | 1.7 | 6.95% ▲ 1.7% vs last year |
| 2024 | 41 | 20 | 2 | 6.83% |
The distance of the line x-22= y-63= z-34 from the point (1,4,0) along the line x1= y-22= z+33 is :
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Let a line pass through two distinct points P(-2,-1,3) and Q, and be parallel to the vector 3 i+2 j+2 k. If the distance of the point Q from the point R(1,3,3) is 5, then the square of the area of PQR is equal to :
The perpendicular distance, of the line x-12= y+2-1= z+32 from the point P(2,-10,1), is :
The shortest distance between the lines x - 34 = y + 7-11 = z - 15 and x - 53 = y - 9-6 = z + 21 is:
Let the line L intersect the lines x - 2 = -y = z - 1, 2(x + 1) = 2(y - 1) = z + 1 and be parallel to the line x - 23 = y - 11 = z - 22. Then which of the following points lies on L ?
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The square of the distance of the image of the point (6, 1, 5) in the line x - 13 = y2 = z - 24, from the origin is .
If the shortest distance between the lines L1 : r = (2 + ) i + (1 - 3 ) j + (3 + 4 ) k, R L2 : r = 2(1 + ) i + 3(1 + ) j + (5 + ) k, R is m n, where (m, n) = 1, then the value of m + n equals
If the shortest distance between the lines x - 2 = y - 43 = z - 34 and x - 24 = y - 46 = z - 78 is 13 29, then a value of is :
Let P( , , ) be the image of the point Q(1, 6, 4) in the line x1 = y - 12 = z - 23. Then 2 + + is equal to
The shortest distance between the lines x - 32 = y + 15-7 = z - 95 and x + 12 = y - 11 = z - 9-3 is
Let P be the point (10, -2, -1) and Q be the foot of the perpendicular drawn from the point R(1, 7, 6) on the line passing through the points (2, -5, 11) and (-6, 7, -5). Then the length of the line segment PQ is equal to .
Let P( , , ) be the image of the point Q(3, -3, 1) in the line x - 01 = y - 31 = z - 1-1 and R be the point (2, 5, -1). If the area of the triangle PQR is and 2 = 14K, then K is equal to :
If the shortest distance between the lines x - 3 = y - 2-1 = z - 11 and x + 2-3 = y + 52 = z - 44 is 44 30, then the largest possible value of | | is equal to .
If the line 2 - x3 = 3y - 24 + 1 = 4 - z makes a right angle with the line x + 33 = 1 - 2y6 = 5 - z7, then 4 + 9 is equal to :
Let d be the distance of the point of intersection of the lines x + 63 = y2 = z + 11 and x - 74 = y - 93 = z - 42 from the point (7, 8, 9). Then d2 + 6 is equal to :
Let ( , , ) be the image of the point (8, 5, 7) in the line x - 12 = y + 13 = z - 25. Then + + is equal to :
Let the point (-1, , ) lie on the line of the shortest distance between the lines x + 2-3 = y - 24 = z - 52 and x + 2-1 = y + 62 = z - 10. Then ( - )2 is equal to .
Let the point, on the line passing through the points P(1,-2,3) and Q(5,-4,7), farther from the origin and at a distance of 9 units from the point P, be ( , , ). Then 2+ 2+ 2 is equal to :
If the shortest distance between the lines x+22= y+33= z-54 and x-31= y-2-3= z+42 is 383 5k, and 0k [x2 ]dx= - , where [x] denotes the greatest integer function, then 6 3 is equal to .
Let P be the point of intersection of the lines x - 21 = y - 45 = z - 21 and x - 32 = y - 23 = z - 32. Then, the shortest distance of P from the line 4x = 2y = z is
Consider a line L passing through the points P(1, 2, 1) and Q(2, 1, -1). If the mirror image of the point A(2, 2, 2) in the line L is ( , , ), then + + 6 is equal to .
If the shortest distance between the lines x- -2= y-21= z-11 and x- 31= y-1-2= z-21 is 1 , then the sum of all possible values of is :
Let the line of the shortest distance between the lines L1: r=( i+2 j+3 k)+ ( i- j+ k) and L2: r=(4 i+5 j+6 k)+ ( i+ j- k) intersect L1 and L2 at P and Q respectively. If ( , , ) is the mid point of the line segment PQ, then 2( + + ) is equal to .
Let P and Q be the points on the line x+38= y-42= z+12 which are at a distance of 6 units from the point R(1,2,3). If the centroid of the triangle PQR is ( , , ), then 2+ 2+ 2 is :
If the mirror image of the point P(3,4,9) in the line x-13= y+12= z-21 is ( , , ), then 14( + + ) is :
The distance of the point Q(0,2,-2) from the line passing through the point P(5,-4,3) and perpendicular to the lines r=(-3 i+2 k)+ (2 i+3 j+5 k), R and r=( i-2 j+ k)+ (- i+3 j+2 k), R is :
Let Q and R be the feet of perpendiculars from the point P(a, a, a) on the lines x=y, z=1 and x=-y, z=-1 respectively. If is a right angle, then 12a2 is equal to .